Solved

Find the Surface Area of the Part of the Parabolic

Question 91

Multiple Choice

Find the surface area of the part of the parabolic cylinder z = 1 - y2 that lies above the triangle with vertices (0, 0, 0) , (0, 1, 0) , and (1, 1, 0) in the xy-plane.


A) Find the surface area of the part of the parabolic cylinder z = 1 - y<sup>2</sup> that lies above the triangle with vertices (0, 0, 0) , (0, 1, 0) , and (1, 1, 0) in the xy-plane. A) ( - 1) square units B) (5 - 1) square units C) ( - 1) square units D) (5 - 1) square units E) ( + 1) square units ( Find the surface area of the part of the parabolic cylinder z = 1 - y<sup>2</sup> that lies above the triangle with vertices (0, 0, 0) , (0, 1, 0) , and (1, 1, 0) in the xy-plane. A) ( - 1) square units B) (5 - 1) square units C) ( - 1) square units D) (5 - 1) square units E) ( + 1) square units - 1) square units
B) Find the surface area of the part of the parabolic cylinder z = 1 - y<sup>2</sup> that lies above the triangle with vertices (0, 0, 0) , (0, 1, 0) , and (1, 1, 0) in the xy-plane. A) ( - 1) square units B) (5 - 1) square units C) ( - 1) square units D) (5 - 1) square units E) ( + 1) square units (5 Find the surface area of the part of the parabolic cylinder z = 1 - y<sup>2</sup> that lies above the triangle with vertices (0, 0, 0) , (0, 1, 0) , and (1, 1, 0) in the xy-plane. A) ( - 1) square units B) (5 - 1) square units C) ( - 1) square units D) (5 - 1) square units E) ( + 1) square units - 1) square units
C) Find the surface area of the part of the parabolic cylinder z = 1 - y<sup>2</sup> that lies above the triangle with vertices (0, 0, 0) , (0, 1, 0) , and (1, 1, 0) in the xy-plane. A) ( - 1) square units B) (5 - 1) square units C) ( - 1) square units D) (5 - 1) square units E) ( + 1) square units ( Find the surface area of the part of the parabolic cylinder z = 1 - y<sup>2</sup> that lies above the triangle with vertices (0, 0, 0) , (0, 1, 0) , and (1, 1, 0) in the xy-plane. A) ( - 1) square units B) (5 - 1) square units C) ( - 1) square units D) (5 - 1) square units E) ( + 1) square units - 1) square units
D) Find the surface area of the part of the parabolic cylinder z = 1 - y<sup>2</sup> that lies above the triangle with vertices (0, 0, 0) , (0, 1, 0) , and (1, 1, 0) in the xy-plane. A) ( - 1) square units B) (5 - 1) square units C) ( - 1) square units D) (5 - 1) square units E) ( + 1) square units (5 Find the surface area of the part of the parabolic cylinder z = 1 - y<sup>2</sup> that lies above the triangle with vertices (0, 0, 0) , (0, 1, 0) , and (1, 1, 0) in the xy-plane. A) ( - 1) square units B) (5 - 1) square units C) ( - 1) square units D) (5 - 1) square units E) ( + 1) square units - 1) square units
E) Find the surface area of the part of the parabolic cylinder z = 1 - y<sup>2</sup> that lies above the triangle with vertices (0, 0, 0) , (0, 1, 0) , and (1, 1, 0) in the xy-plane. A) ( - 1) square units B) (5 - 1) square units C) ( - 1) square units D) (5 - 1) square units E) ( + 1) square units ( Find the surface area of the part of the parabolic cylinder z = 1 - y<sup>2</sup> that lies above the triangle with vertices (0, 0, 0) , (0, 1, 0) , and (1, 1, 0) in the xy-plane. A) ( - 1) square units B) (5 - 1) square units C) ( - 1) square units D) (5 - 1) square units E) ( + 1) square units + 1) square units

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions

Q86: Where is the centre of mass of

Q87: The surfaces y = 4 - x2,

Q88: The surfaces x + y + z

Q89: Find the surface area of the

Q90: Find the surface area S of

Q92: Find the mass of a plate in

Q93: Find the mass of a circular

Q94: Let D be the planar region occupied

Q95: Find the mass of a spherical

Q96: The surfaces x = 0, y =

Unlock this Answer For Free Now!

View this answer and more for free by performing one of the following actions

qr-code

Scan the QR code to install the App and get 2 free unlocks

upload documents

Unlock quizzes for free by uploading documents