Solve the initial-value problem = 1 + , (0) = 1, y(0) = 0.
A) y = -ln(cos(x) - sin(x))
B) y = ln(cos(x) - sin(x))
C) y = -ln(sin(x) - cos(x))
D) y = ln(sin(x) - cos(x))
E) None of the above

Question

Solve the initial-value problem  = 1 +  ,  (0) = 1, y(0) = 0.
A) y = -ln(cos(x) - sin(x)) 
B) y = ln(cos(x) - sin(x)) 
C) y = -ln(sin(x) - cos(x)) 
D) y = ln(sin(x) - cos(x)) 
E) None of the above

Quizplus · Accepted Answer

The Answer of Solve the initial-value problem  = 1 +  ,  (0) = 1, y(0) = 0.
A) y = -ln(cos(x) - sin(x)) 
B) y = ln(cos(x) - sin(x)) 
C) y = -ln(sin(x) - cos(x)) 
D) y = ln(sin(x) - cos(x)) 
E) None of the above

Solve the Initial-Value Problem = 1