Two 1.5-V batteries placed end-to-end power a flashlight. If the current in the circuit is 0.6 A, what is the resistance in the bulb?
A) 5.0 $\Omega$
B) 2.5 $\Omega$
C) 1.8 $\Omega$
D) 0.9 $\Omega$

Question

Two 1.5-V batteries placed end-to-end power a flashlight. If the current in the circuit is 0.6 A, what is the resistance in the bulb?
A) 5.0  $\Omega$
B) 2.5  $\Omega$
C) 1.8  $\Omega$
D) 0.9  $\Omega$

Quizplus · Accepted Answer

The resistance in the bulb can be calculated using Ohm's law: R = V/I. In this case, the voltage is 3 V (since the two batteries are placed end-to-end) and the current is 0.6 A. Therefore, the resistance is R = 3 V / 0.6 A = 5 $\Omega$.

Two 15-V Batteries Placed End-To-End Power a Flashlight Ω\OmegaΩ B) 25 Ω\OmegaΩ

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