A 2 x 3 factorial ANOVA with nine scores per cell produced a MS_AB = 18.75 and a MS_error = 7.5. For the factor with 3 levels and $\alpha$ = .05, a Tukey HSD would A) not be appropriate in this instance B) find a mean difference of 3.60 significant C) find a mean difference of 3.80 significant D) find mean differences of both 3.60 and 3.80 significant E) find differences of neither 3.60 nor 3.80 significant.

Question

Quizplus · Accepted Answer

The Tukey HSD (Honestly Significant Difference) test is used to determine if the means of any two groups are significantly different from each other. It is appropriate in this instance because it is designed for use after an ANOVA when you have a significant result and want to explore which specific group means are different. The formula for the Tukey HSD involves the mean square error (MSE) and the number of scores per group, both of which are provided. Given that both mean differences of 3.60 and 3.80 are considered significant, it implies that the calculated HSD value is lower than these differences, making option D correct.

A 2 X 3 Factorial ANOVA with Nine Scores Per α\alphaα

A 2 X 3 Factorial ANOVA with Nine Scores Per $\alpha$