Summary statistics from a sample were: $\Sigma$X² = 66, $\Sigma$X = 12, and N = 4. The standard error of the mean is A) 0.79 B) 1.37 C) 1.58 D) 2.50 E) 5.00

Question

Quizplus · Accepted Answer

The standard error of the mean is the standard deviation of the sample divided by the square root of the sample size. In this case, the standard deviation is $\sqrt{\frac{\Sigma X^2 - (\Sigma X)^2/N}{N-1}} = \sqrt{\frac{66 - (12)^2/4}{4-1}} = 3.16$. The standard error of the mean is then $\frac{3.16}{\sqrt{4}} = 1.58$.

Summary Statistics from a Sample Were Σ\SigmaΣ X2 = 66 Σ\SigmaΣ X = 12, and N = 4

Summary Statistics from a Sample Were $\Sigma$ X² = 66 $\Sigma$ X = 12, and N = 4