Find $\lim _ { x \rightarrow 0 } \frac { \cos x - 1 } { 2 \sin x }$
A) 1/2
B) 0
C) 1
D) Does not exist

Name: Find $\lim _ { x \rightarrow 0 } \frac { \cos x - 1 } { 2 \sin x }$ A) 1/2 B) 0 C) 1 D) Does not exist
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Question

Quizplus · Accepted Answer

The limit can be evaluated using L'Hôpital's Rule, which applies to indeterminate forms like 0/0. Differentiating the numerator and denominator gives $-\sin x$ and $2\cos x$, respectively. Evaluating the limit as $x$ approaches 0 gives 0.

Find lim⁡x→0cos⁡x−12sin⁡x\lim _ { x \rightarrow 0 } \frac { \cos x - 1 } { 2 \sin x }limx→0​2sinxcosx−1​

Find $\lim _ { x \rightarrow 0 } \frac { \cos x - 1 } { 2 \sin x }$