Use the Intermediate Value Theorem to find a $c \in ( - \infty , \infty )$ for $f ( x ) = x ^ { 3 } + 2$ on the interval [-2, 3] such that $f ( c ) = 1$

Name: Use the Intermediate Value Theorem to find a $c \in ( - \infty , \infty )$ for $f ( x ) = x ^ { 3 } + 2$ on the interval [-2, 3] such that $f ( c ) = 1$
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