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Question 24
Xg(x) h(x) g′(x) h′(x) −30310−2122−3−130−1−2023−2310−1−2−22−2−2−103−3001\begin{array} { | l | l | l | l | l | } \hline \mathrm { X } & \mathrm { g } ( \mathrm { x } ) & \mathrm { h } ( \mathrm { x } ) & \mathrm { g } ^ { \prime } ( \mathrm { x } ) & \mathrm { h } ^ { \prime } ( \mathrm { x } ) \\\hline - 3 & 0 & 3 & 1 & 0 \\\hline - 2 & 1 & 2 & 2 & - 3 \\\hline - 1 & 3 & 0 & - 1 & - 2 \\\hline 0 & 2 & 3 & - 2 & 3 \\\hline 1 & 0 & - 1 & - 2 & - 2 \\\hline 2 & - 2 & - 2 & - 1 & 0 \\\hline 3 & - 3 & 0 & 0 & 1 \\\hline\end{array}X−3−2−10123g(x) 01320−2−3h(x) 3203−1−20g′(x) 12−1−2−2−10h′(x) 0−3−23−201 -Use the table above to find f′(3) f ^ { \prime } ( 3 ) f′(3) if f(x) =5g(x) −4h(x) f ( x ) = 5 g ( x ) - 4 h ( x ) f(x) =5g(x) −4h(x)
A) 4B) - 1C) 1D) - 4
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