A 5-kg mass is pulled up a smooth incline at a constant speed by a rope. The rope is parallel with the surface of the incline. If the incline is 50° relative to the horizontal, the tension in the rope is
A) 38 N.
B) 41 N.
C) 44 N.
D) 49 N.

Question

Quizplus · Accepted Answer

The tension in the rope is equal to the force required to pull the mass up the incline, which is equal to the weight of the mass times the sine of the angle of the incline. Therefore, the tension in the rope is:T = mg * sin(theta) = 5 kg * 9.8 m/s^2 * sin(50°) = 38 N

A 5-Kg Mass Is Pulled Up a Smooth Incline at a Constant