Find the slope and y-intercept of the line whose equation is given. $\frac { x } { 2 } + \frac { y } { 3 } = 1$
A) Slope: $\frac { 3 } { 2 }$ ; y-intercept: $\frac { 1 } { 2 }$
B) Slope: $- \frac { 3 } { 2 }$ ; y-intercept: 3
C) Slope: $\frac { 3 } { 2 }$ ; y-intercept: 1
D) Slope: $\frac { 1 } { 2 }$ ; y-intercept: 1

Question

Quizplus · Accepted Answer

To find the slope and y-intercept, we first rewrite the equation in slope-intercept form, $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept. Starting with $\frac{x}{2} + \frac{y}{3} = 1$, multiplying everything by 6 (the least common multiple of 2 and 3) to clear the denominators gives $3x + 2y = 6$. Then, solving for $y$ gives $y = -\frac{3}{2}x + 3$. Thus, the slope is $-\frac{3}{2}$ and the y-intercept is 3.

Find the Slope and Y-Intercept of the Line Whose Equation x2+y3=1\frac { x } { 2 } + \frac { y } { 3 } = 12x​+3y​=1

Find the Slope and Y-Intercept of the Line Whose Equation $\frac { x } { 2 } + \frac { y } { 3 } = 1$