$$f ( x ) = \left\{ \begin{array} { l l }
\frac { 7 } { x ^ { 8 } } & \text { if } x \geq 1 \
0 & \text { if } x

Question

$$f ( x ) = \left\{ \begin{array} { l l } 
\frac { 7 } { x ^ { 8 } } & \text { if } x \geq 1 \
0 & \text { if } x < 1
\end{array} \right.$$ is a probability density function for a particular random variable X Use integration to find $P ( X \geq 3 )$

Quizplus · Accepted Answer

The Answer of $$f ( x ) = \left\{ \begin{array} { l l } 
\frac { 7 } { x ^ { 8 } } & \text { if } x \geq 1 \
0 & \text { if } x < 1
\end{array} \right.$$ is a probability density function for a particular random variable X Use integration to find $P ( X \geq 3 )$

f(x)={7x8 if x≥10 if x<1f ( x ) = \left\{ \begin{array} { l l } \frac { 7 } { x ^ { 8 } } & \text { if } x \geq 1 \\0 & \text { if } x < 1\end{array} \right.f(x)={x87​0​ if x≥1 if x<1​

$f ( x ) = \left\{ \begin{array} { l l } \frac { 7 } { x ^ { 8 } } & \text { if } x \geq 1 \\0 & \text { if } x < 1\end{array} \right.$