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∫x3−3x2+8xdx=x33−3x22+8ln⁡∣x∣+C\int \frac { x ^ { 3 } - 3 x ^ { 2 } + 8 } { x } d x = \frac { x ^ { 3 } } { 3 } - \frac { 3 x ^ { 2 } } { 2 } + 8 \ln | x | + C

Question 40

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∫x3−3x2+8xdx=x33−3x22+8ln⁡∣x∣+C\int \frac { x ^ { 3 } - 3 x ^ { 2 } + 8 } { x } d x = \frac { x ^ { 3 } } { 3 } - \frac { 3 x ^ { 2 } } { 2 } + 8 \ln | x | + C

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