$\int ( x + 6 ) ^ { - 11 } d x = - \frac { ( x - 6 ) ^ { - 12 } } { 12 } + C$

Name: $\int ( x + 6 ) ^ { - 11 } d x = - \frac { ( x - 6 ) ^ { - 12 } } { 12 } + C$
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Question

Quizplus · Accepted Answer

The correct antiderivative should be $\int ( x + 6 ) ^ { - 11 } d x = \frac { ( x + 6 ) ^ { - 10 } } { -10 } + C$, and there is a sign mistake in the given answer.

∫(x+6)−11dx=−(x−6)−1212+C\int ( x + 6 ) ^ { - 11 } d x = - \frac { ( x - 6 ) ^ { - 12 } } { 12 } + C∫(x+6)−11dx=−12(x−6)−12​+C

$\int ( x + 6 ) ^ { - 11 } d x = - \frac { ( x - 6 ) ^ { - 12 } } { 12 } + C$