If the energy of n = 6 is -0.378 eV and that of n = 5 is -0.544 eV in a hydrogen atom, a transition from n = 6 to n = 5 will _______________ a photon with an energy of approximately ______________.
A) absorb; 0.922 eV
B) emit; 0.166 eV
C) absorb; 0.166 eV
D) emit; 0.922 eV

Question

Quizplus · Accepted Answer

The energy difference between the two states is 0.544 eV - 0.378 eV = 0.166 eV. Since the energy of the n = 6 state is higher than that of the n = 5 state, transitioning from n = 6 to n = 5 will release energy, meaning a photon will be emitted with an energy of approximately 0.166 eV.

If the Energy of N = 6 Is -0