For a Wilkinson power divider of insertion loss L and the coupler is matched to the external circuitry, and then the gain of the coupler in terms of insertion loss is:
A)2L
B)1/2L
C)l
D)1/l

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The Answer of For a Wilkinson power divider of insertion loss L and the coupler is matched to the external circuitry, and then the gain of the coupler in terms of insertion loss is:
A)2L
B)1/2L
C)l
D)1/l

For a Wilkinson Power Divider of Insertion Loss L and the Coupler