An inductor is operating at frequency of 50 MHz. Its inductance is 0.1 µH, and then the series resistance associated with the inductor is: (Qo=100)
A)0.31 ?
B)1.32 ?
C)1 ?
D)1.561 ?

Question

Quizplus · Accepted Answer

The quality factor (Qo) is given by Qo = (2 * π * f * L) / R, where f is the frequency, L is the inductance, and R is the series resistance. Solving for R gives R = (2 * π * 50 * 10^6 * 0.1 * 10^-6) / 100 = 0.31 Ω.

An Inductor Is Operating at Frequency of 50 MHz