If a student drops a stone from a cliff of height 30 m and the time it takes to reach the ground is 2.6 s, then the acceleration due to gravity is A)9ms^-2 B)10ms^-2 C)4ms^-2 D)8.8ms^-2

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Quizplus · Accepted Answer

Using the formula $s = ut + \frac{1}{2}gt^2$ where $s$ is the distance, $u$ is the initial velocity (0 in this case since the stone is dropped), $g$ is the acceleration due to gravity, and $t$ is the time, we can solve for $g$. Plugging in $s = 30m$ and $t = 2.6s$, we get $30 = 0 + \frac{1}{2}g(2.6)^2$. Solving for $g$ gives approximately $8.8 \, \text{m/s}^2$.

If a Student Drops a Stone from a Cliff of Height