For the following data from a repeated-measures study,the sample mean difference is MD = 1.
$$\begin{array} { c r r }
\text { Participant } & X _ { 1 } & X _ { 2 } \
\hline \mathrm { A } & 1 & 5 \
\mathrm {~B} & 4 & 6 \
\mathrm { C } & 5 & 2
\end{array}$$

Question

For the following data from a repeated-measures study,the sample mean difference is MD = 1.
 $$\begin{array} { c r r } 
\text { Participant } & X _ { 1 } & X _ { 2 } \
\hline \mathrm { A } & 1 & 5 \
\mathrm {~B} & 4 & 6 \
\mathrm { C } & 5 & 2
\end{array}$$

Quizplus · Accepted Answer

To find the sample mean difference, we need to calculate the difference between X1 and X2 for each participant, then calculate the mean of those differences. For participant A, the difference is 5 - 1 = 4. For participant B, the difference is 6 - 4 = 2. For participant C, the difference is 2 - 5 = -3. The mean of these differences is (4 + 2 - 3) / 3 = 1. Therefore, the sample mean difference is MD = 1.

For the Following Data from a Repeated-Measures Study,the Sample Mean