A normal distribution has a mean of µ = 70 with σ = 10.If one score is randomly selected from this distribution,what is the probability that the score will be greater than X = 82?
A)0.7698
B)0.3849
C)0.1151
D)0.8849

Question

Quizplus · Accepted Answer

We need to find the probability that a score is greater than X=82, using the mean (µ = 70) and standard deviation (σ = 10).

First, we need to calculate the z-score:
z = (X - µ) / σ = (82 - 70) / 10 = 1.2

Then, we can use a standard normal distribution table or calculator to find the probability corresponding to this z-score:
P(Z>1.2) = 0.1151

Therefore, the probability that a score is greater than X=82 is 0.1151 or 11.51%. 
The best choice is C.

A Normal Distribution Has a Mean of µ = 70