Consider the reaction $$\begin{array} { l } P _ { s a } \stackrel { k _ { 1 } } { \longrightarrow } Q _ { s a } + e ^ { - } \ A _ { s i l } ^ { - } \underset { k _ { - 2 } } { \stackrel { k _ { 2 } } { \rightleftarrows } } A _ { \alpha i j } + e ^ { - } \ \end{array}$$ The kinetic parameters are given by k 10 = 10 -5 cm s -1 , b 1 = 20 V -1 , k 20 = 10 -6 cm s -1 , b 2 = 20 V -1 , k -20 =10 -6 mol cm -2 s -1 , b -2 = -18 V -1 and $\varGamma$ = 10 -8 mol cm -2 . Solution species concentrations are given by [P sol ] = [Q sol ] =[ $$A _ { s o l } ^ { - }$$ ] = 100 mM. -The equation for fractional surface coverage of A_ads is given by A) $$\frac { k _ { 2 \dot { dc } } } { k _ { 2 k \dot { dc } } + k _ { - 2 \dot { dc } } + k _ { 1 \dot { dc } } }$$ B) $$\frac { k _ { 2 dc } } { k _ { 2dc } + k _ { - 2 \dot {dc } } }$$ C) $\frac{k_{2 dc} C_{\mathcal{A}^-_{\mathrm{sol}}}}{k_{2 dc} C_{A^-_{sol}}+k_{-2 d c}+k_{1 d c} C_{P_{sol}}}$ D) $\frac{k_{2 dc} C_{A^-_{sol}}}{k_{2 dc} C_{A^-_{sol}}+k_{-2dc}}$

Question

Quizplus · Accepted Answer

The fractional surface coverage of $A_{\text{ads}}$ is determined by the balance between its adsorption rate ($k_{2dc} C_{A^-_{sol}}$) and its desorption rate ($k_{-2dc}$). The presence of $k_{1dc}$ in the denominator of options A and C is incorrect because it pertains to a different reaction pathway that does not directly influence the adsorption-desorption equilibrium of $A_{\text{ads}}$. Option B is incorrect due to a typographical error in the subscript notation. Therefore, option D correctly represents the fractional surface coverage of $A_{\text{ads}}$ by considering only the processes directly involved in its adsorption and desorption.

Consider the Reaction The Kinetic Parameters Are Given by K10 = 10-5 cm

Consider the Reaction The Kinetic Parameters Are Given by K₁₀ = 10^-5cm