Suppose a normal distribution of scores has a mean of 200 and a standard deviation of 20. What is the score in the distribution below which 97.5% of the scores would fall?
A) 210.0
B) 220.0
C) 232.8
D) 239.2

Question

Quizplus · Accepted Answer

The z-score corresponding to a cumulative probability of 0.975 is 1.96. The score in the distribution below which 97.5% of the scores would fall is therefore 200 + (1.96 * 20) = 239.2.

Suppose a Normal Distribution of Scores Has a Mean of 200