Let $P _ { 1 } = ( 1,3,5 )$ and $P _ { 2 } = ( - 2,4 , - 6 )$ v is $\overrightarrow { P _ { 1 } P _ { 2 } }$ in standard position, then v is

A) $\langle 3,1 , - 11 \rangle$
B) $\langle 3 , - 1 , - 11 \rangle$
C) $\langle - 3 , - 1 , - 11 \rangle$
D) $\langle - 3 , - 1,11 \rangle$
E) $\langle - 3,1 , - 11 \rangle$

Question

Let $P _ { 1 } = ( 1,3,5 )$ and $P _ { 2 } = ( - 2,4 , - 6 )$ v is $\overrightarrow { P _ { 1 } P _ { 2 } }$ in standard position, then v is

A) $\langle 3,1 , - 11 \rangle$
B) $\langle 3 , - 1 , - 11 \rangle$
C) $\langle - 3 , - 1 , - 11 \rangle$
D) $\langle - 3 , - 1,11 \rangle$
E) $\langle - 3,1 , - 11 \rangle$

Quizplus · Accepted Answer

The Answer of Let $P _ { 1 } = ( 1,3,5 )$ and $P _ { 2 } = ( - 2,4 , - 6 )$ v is $\overrightarrow { P _ { 1 } P _ { 2 } }$ in standard position, then v is

A) $\langle 3,1 , - 11 \rangle$
B) $\langle 3 , - 1 , - 11 \rangle$
C) $\langle - 3 , - 1 , - 11 \rangle$
D) $\langle - 3 , - 1,11 \rangle$
E) $\langle - 3,1 , - 11 \rangle$

Let P1=(1,3,5)P _ { 1 } = ( 1,3,5 )P1​=(1,3,5) And P2=(−2,4,−6)P _ { 2 } = ( - 2,4 , - 6 )P2​=(−2,4,−6)

Let $P _ { 1 } = ( 1,3,5 )$ And $P _ { 2 } = ( - 2,4 , - 6 )$