The solution r(t) to the differential equation r′(t) =6t2i−etj+e−tk with the condition r(0) =3i+j−2k is
A) −(2t3+3) i+(et−2) j−(e−t+1) k B) −(2t3+3) i−(et−2) j+(e−t+1) k C) (2t3+3) i+(et−2) j−(e−t+1) k D) (2t3+3) i−(et−2) j+(e−t+1) k E) (2t3+3) i−(et−2) j−(e−t+1) k
Correct Answer:
Verified
Unlock this answer now Get Access to more Verified Answers free of charge