The symmetric equations of the normal line to the surface $y = e ^ { x } \cos z$ at (1, e, 0) are

A) $\frac { x - 1 } { 2 e } = y - e , z = 0$
B) $\frac { x - 1 } { - 2 e } = y - e , z = 0$
C) $\frac { x - 1 } { 3 e } = y - e , z = 0$
D) $\frac { x - 1 } { e } = y - e , z = 0$
E) $\frac { x - 1 } { - e } = y - e , z = 0$

Question

The symmetric equations of the normal line to the surface $y = e ^ { x } \cos z$ at (1, e, 0) are

A) $\frac { x - 1 } { 2 e } = y - e , z = 0$
B) $\frac { x - 1 } { - 2 e } = y - e , z = 0$
C) $\frac { x - 1 } { 3 e } = y - e , z = 0$
D) $\frac { x - 1 } { e } = y - e , z = 0$
E) $\frac { x - 1 } { - e } = y - e , z = 0$

Quizplus · Accepted Answer

The Answer of The symmetric equations of the normal line to the surface $y = e ^ { x } \cos z$ at (1, e, 0) are

A) $\frac { x - 1 } { 2 e } = y - e , z = 0$
B) $\frac { x - 1 } { - 2 e } = y - e , z = 0$
C) $\frac { x - 1 } { 3 e } = y - e , z = 0$
D) $\frac { x - 1 } { e } = y - e , z = 0$
E) $\frac { x - 1 } { - e } = y - e , z = 0$

The Symmetric Equations of the Normal Line to the Surface y=excos⁡zy = e ^ { x } \cos zy=excosz

The Symmetric Equations of the Normal Line to the Surface $y = e ^ { x } \cos z$