Let $f ( x , y , z ) = \sqrt { x ^ { 2 } + y ^ { 2 } + z ^ { 2 } }$ . Then the maximum value of the directional derivative $D _ { \mathrm { u } } f ( 3,4,0 )$ is

A)5
B)3
C)2
D)1
E) $\frac { 1 } { 3 }$

Question

Let $f ( x , y , z ) = \sqrt { x ^ { 2 } + y ^ { 2 } + z ^ { 2 } }$ . Then the maximum value of the directional derivative $D _ { \mathrm { u } } f ( 3,4,0 )$ is

A)5
B)3
C)2
D)1
E) $\frac { 1 } { 3 }$

Quizplus · Accepted Answer

The Answer of Let $f ( x , y , z ) = \sqrt { x ^ { 2 } + y ^ { 2 } + z ^ { 2 } }$ . Then the maximum value of the directional derivative $D _ { \mathrm { u } } f ( 3,4,0 )$ is

A)5
B)3
C)2
D)1
E) $\frac { 1 } { 3 }$

Let f(x,y,z)=x2+y2+z2f ( x , y , z ) = \sqrt { x ^ { 2 } + y ^ { 2 } + z ^ { 2 } }f(x,y,z)=x2+y2+z2​

Let $f ( x , y , z ) = \sqrt { x ^ { 2 } + y ^ { 2 } + z ^ { 2 } }$