The surface area of the surface z = 2xy in the first octant lying inside $4 x ^ { 2 } + 4 y ^ { 2 } = 1$ is

A) $\frac { \pi ( 2 \sqrt { 2 } - 1 ) } { 4 }$
B) $\frac { \pi ( 2 \sqrt { 2 } - 1 ) } { 6 }$
C) $\frac { \pi ( 2 \sqrt { 2 } - 1 ) } { 24 }$
D) $\frac { \pi ( 2 \sqrt { 2 } - 1 ) } { 8 }$
E) $\frac { \pi ( 2 \sqrt { 2 } - 1 ) } { 3 }$

Question

The surface area of the surface z = 2xy in the first octant lying inside $4 x ^ { 2 } + 4 y ^ { 2 } = 1$ is

A) $\frac { \pi ( 2 \sqrt { 2 } - 1 ) } { 4 }$
B) $\frac { \pi ( 2 \sqrt { 2 } - 1 ) } { 6 }$
C) $\frac { \pi ( 2 \sqrt { 2 } - 1 ) } { 24 }$
D) $\frac { \pi ( 2 \sqrt { 2 } - 1 ) } { 8 }$
E) $\frac { \pi ( 2 \sqrt { 2 } - 1 ) } { 3 }$

Quizplus · Accepted Answer

The Answer of The surface area of the surface z = 2xy in the first octant lying inside $4 x ^ { 2 } + 4 y ^ { 2 } = 1$ is

A) $\frac { \pi ( 2 \sqrt { 2 } - 1 ) } { 4 }$
B) $\frac { \pi ( 2 \sqrt { 2 } - 1 ) } { 6 }$
C) $\frac { \pi ( 2 \sqrt { 2 } - 1 ) } { 24 }$
D) $\frac { \pi ( 2 \sqrt { 2 } - 1 ) } { 8 }$
E) $\frac { \pi ( 2 \sqrt { 2 } - 1 ) } { 3 }$

The Surface Area of the Surface Z = 2xy in the First