The area bounded by $x ^ { 2 } + y ^ { 2 } = 16$ and $y ^ { 2 } = 6 x$ is

A) $\frac { 4 ( 9 \sqrt { 3 } + 2 + 6 \pi ) } { 9 }$
B) $\frac { 4 ( 9 \sqrt { 3 } + 6 \pi ) } { 9 }$
C) $\frac { 4 ( 9 \sqrt { 3 } - 2 + 6 \pi ) } { 9 }$
D) $\frac { - 4 ( 9 \sqrt { 3 } + 6 \pi ) } { 9 }$
E) $\frac { - 4 ( 9 \sqrt { 3 } + 2 + 6 \pi ) } { 9 }$

Question

The area bounded by $x ^ { 2 } + y ^ { 2 } = 16$ and $y ^ { 2 } = 6 x$ is

A) $\frac { 4 ( 9 \sqrt { 3 } + 2 + 6 \pi ) } { 9 }$
B) $\frac { 4 ( 9 \sqrt { 3 } + 6 \pi ) } { 9 }$
C) $\frac { 4 ( 9 \sqrt { 3 } - 2 + 6 \pi ) } { 9 }$
D) $\frac { - 4 ( 9 \sqrt { 3 } + 6 \pi ) } { 9 }$
E) $\frac { - 4 ( 9 \sqrt { 3 } + 2 + 6 \pi ) } { 9 }$

Quizplus · Accepted Answer

The Answer of The area bounded by $x ^ { 2 } + y ^ { 2 } = 16$ and $y ^ { 2 } = 6 x$ is

A) $\frac { 4 ( 9 \sqrt { 3 } + 2 + 6 \pi ) } { 9 }$
B) $\frac { 4 ( 9 \sqrt { 3 } + 6 \pi ) } { 9 }$
C) $\frac { 4 ( 9 \sqrt { 3 } - 2 + 6 \pi ) } { 9 }$
D) $\frac { - 4 ( 9 \sqrt { 3 } + 6 \pi ) } { 9 }$
E) $\frac { - 4 ( 9 \sqrt { 3 } + 2 + 6 \pi ) } { 9 }$

The Area Bounded By x2+y2=16x ^ { 2 } + y ^ { 2 } = 16x2+y2=16

The Area Bounded By $x ^ { 2 } + y ^ { 2 } = 16$