The area of the surface $\mathbf { r } ( u , v ) = 2 u \cos v \mathbf { i } + 2 u \sin v \mathbf { j } + u \mathbf { k }$ , where is

A) $6 \pi \sqrt { 5 }$
B) $5 \pi \sqrt { 5 }$
C) $4 \pi \sqrt { 5 }$
D) $3 \pi \sqrt { 5 }$
E) $2 \pi \sqrt { 5 }$

Question

The area of the surface $\mathbf { r } ( u , v ) = 2 u \cos v \mathbf { i } + 2 u \sin v \mathbf { j } + u \mathbf { k }$ , where is

A) $6 \pi \sqrt { 5 }$
B) $5 \pi \sqrt { 5 }$
C) $4 \pi \sqrt { 5 }$
D) $3 \pi \sqrt { 5 }$
E) $2 \pi \sqrt { 5 }$

Quizplus · Accepted Answer

The Answer of The area of the surface $\mathbf { r } ( u , v ) = 2 u \cos v \mathbf { i } + 2 u \sin v \mathbf { j } + u \mathbf { k }$ , where is

A) $6 \pi \sqrt { 5 }$
B) $5 \pi \sqrt { 5 }$
C) $4 \pi \sqrt { 5 }$
D) $3 \pi \sqrt { 5 }$
E) $2 \pi \sqrt { 5 }$

The Area of the Surface r(u,v)=2ucos⁡vi+2usin⁡vj+uk\mathbf { r } ( u , v ) = 2 u \cos v \mathbf { i } + 2 u \sin v \mathbf { j } + u \mathbf { k }r(u,v)=2ucosvi+2usinvj+uk