The fourth derivative $\frac { d ^ { 4 } } { d x ^ { 4 } } \left( x ^ { 2 } - e ^ { x } \right)$ is

A) $2 x - e ^ { x }$
B) $2 - e ^ { x }$
C) $2 + e ^ { x }$
D) $- e ^ { x }$
E) $e ^ { x }$

Question

The fourth derivative $\frac { d ^ { 4 } } { d x ^ { 4 } } \left( x ^ { 2 } - e ^ { x } \right)$ is

A) $2 x - e ^ { x }$
B) $2 - e ^ { x }$
C) $2 + e ^ { x }$
D) $- e ^ { x }$
E) $e ^ { x }$

Quizplus · Accepted Answer

The fourth derivative of $x^2$ is 0 since any power of $x$ lower than 4 will result in 0 when differentiated four times. The fourth derivative of $-e^x$ remains $-e^x$, as the exponential function's derivative is itself.

The Fourth Derivative d4dx4(x2−ex)\frac { d ^ { 4 } } { d x ^ { 4 } } \left( x ^ { 2 } - e ^ { x } \right)dx4d4​(x2−ex)

The Fourth Derivative $\frac { d ^ { 4 } } { d x ^ { 4 } } \left( x ^ { 2 } - e ^ { x } \right)$