Letting $f ( x ) = \sqrt { x }$ and $x _ { 0 } = 25$ the approximation of $\sqrt { 24 }$ by differentials is

A)5.1
B)5.05
C)4.95
D)4.9
E)4.85

Name: Letting $f ( x ) = \sqrt { x }$ and $x _ { 0 } = 25$ the approximation of $\sqrt { 24 }$ by differentials is A)5.1 B)5.05 C)4.95 D)4.9 E)4.85
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Question

Letting $f ( x ) = \sqrt { x }$ and $x _ { 0 } = 25$ the approximation of $\sqrt { 24 }$ by differentials is

A)5.1
B)5.05
C)4.95
D)4.9
E)4.85

Quizplus · Accepted Answer

The Answer of Letting $f ( x ) = \sqrt { x }$ and $x _ { 0 } = 25$ the approximation of $\sqrt { 24 }$ by differentials is

A)5.1
B)5.05
C)4.95
D)4.9
E)4.85

Letting f(x)=xf ( x ) = \sqrt { x }f(x)=x​ And x0=25x _ { 0 } = 25x0​=25

Letting $f ( x ) = \sqrt { x }$ And $x _ { 0 } = 25$