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Question 80
Let f(x) =−x3−6x2−9x+1f ( x ) = - x ^ { 3 } - 6 x ^ { 2 } - 9 x + 1f(x) =−x3−6x2−9x+1 Then ƒ has a relative minimum at x =
A) -3B) -2C) -1D) 0E) 2
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