Solved

Let V Be the Volume of the Solid That Lies y=x29y = \frac { x ^ { 2 } } { 9 }

Question 79

Multiple Choice

Let V be the volume of the solid that lies between planes perpendicular to the x-axis from x = 0 to x = 3. The cross-sections of this solid perpendicular to the x-axis run from y=x29y = \frac { x ^ { 2 } } { 9 } to y=x3y = \sqrt { \frac { x } { 3 } } and they are equilateral triangles with bases in the xy-plane. Then V is


A) 273280\frac { 27 \sqrt { 3 } } { 280 }
B) 273140\frac { 27 \sqrt { 3 } } { 140 }
C) 27370\frac { 27 \sqrt { 3 } } { 70 }
D) 27335\frac { 27 \sqrt { 3 } } { 35 }
E) 273350\frac { 27 \sqrt { 3 } } { 350 }

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions

Unlock this Answer For Free Now!

View this answer and more for free by performing one of the following actions

qr-code

Scan the QR code to install the App and get 2 free unlocks

upload documents

Unlock quizzes for free by uploading documents