The sequence $\{ \sin n \}$ is

A)bounded from above only
B)bounded from below only
C)bounded from both above and below
D)decreasing
E)increasing

Question

The sequence $\{ \sin n \}$ is

A)bounded from above only
B)bounded from below only
C)bounded from both above and below
D)decreasing
E)increasing

Quizplus · Accepted Answer

The sequence $\{ \sin n \}$ is bounded because the sine function itself is bounded for all real numbers, with its values always lying in the interval $[-1, 1]$. This means it is bounded from both above and below, but it is neither increasing nor decreasing due to the periodic and oscillatory nature of the sine function.

The Sequence {sin⁡n}\{ \sin n \}{sinn} Is A)bounded from Above Only B)bounded from Below Only

The Sequence $\{ \sin n \}$ Is

A)bounded from Above Only
B)bounded from Below Only