The rectangular equation of the conic section $r = \frac { 2 } { 6 + 2 \sin \theta }$ is

A) $3 y ^ { 2 } = 1 - 2 x$
B) $36 x ^ { 2 } + 32 y ^ { 2 } - 4 y = 1$
C) $36 x ^ { 2 } + 32 y ^ { 2 } + 4 x = 1$
D) $36 x ^ { 2 } + 32 y ^ { 2 } + 8 y = 4$
E) $36 x ^ { 2 } + 32 y ^ { 2 } - 4 x = 1$

Question

The rectangular equation of the conic section $r = \frac { 2 } { 6 + 2 \sin \theta }$ is

A) $3 y ^ { 2 } = 1 - 2 x$
B) $36 x ^ { 2 } + 32 y ^ { 2 } - 4 y = 1$
C) $36 x ^ { 2 } + 32 y ^ { 2 } + 4 x = 1$
D) $36 x ^ { 2 } + 32 y ^ { 2 } + 8 y = 4$
E) $36 x ^ { 2 } + 32 y ^ { 2 } - 4 x = 1$

Quizplus · Accepted Answer

The Answer of The rectangular equation of the conic section $r = \frac { 2 } { 6 + 2 \sin \theta }$ is

A) $3 y ^ { 2 } = 1 - 2 x$
B) $36 x ^ { 2 } + 32 y ^ { 2 } - 4 y = 1$
C) $36 x ^ { 2 } + 32 y ^ { 2 } + 4 x = 1$
D) $36 x ^ { 2 } + 32 y ^ { 2 } + 8 y = 4$
E) $36 x ^ { 2 } + 32 y ^ { 2 } - 4 x = 1$

The Rectangular Equation of the Conic Section r=26+2sin⁡θr = \frac { 2 } { 6 + 2 \sin \theta }r=6+2sinθ2​

The Rectangular Equation of the Conic Section $r = \frac { 2 } { 6 + 2 \sin \theta }$