The solution set of the equation $\frac { 6 x - 5 } { 2 x + 1 } = \log _ { 4 } 64$ is

A) $\varnothing$
B){1}
C){2}
D){3}
E){4}

Name: The solution set of the equation $\frac { 6 x - 5 } { 2 x + 1 } = \log _ { 4 } 64$ is A) $\varnothing$ B){1} C){2} D){3} E){4}
Brand: Quizplus
Rating: 4.8 (33 reviews)

Question

The solution set of the equation $\frac { 6 x - 5 } { 2 x + 1 } = \log _ { 4 } 64$ is

A) $\varnothing$
B){1}
C){2}
D){3}
E){4}

Quizplus · Accepted Answer

The Answer of The solution set of the equation $\frac { 6 x - 5 } { 2 x + 1 } = \log _ { 4 } 64$ is

A) $\varnothing$
B){1}
C){2}
D){3}
E){4}

The Solution Set of the Equation 6x−52x+1=log⁡464\frac { 6 x - 5 } { 2 x + 1 } = \log _ { 4 } 642x+16x−5​=log4​64

The Solution Set of the Equation $\frac { 6 x - 5 } { 2 x + 1 } = \log _ { 4 } 64$