Let $f ( x ) = x + \frac { 1 } { x }$ and $g ( x ) = \frac { 1 } { x }$ Then the domain of $g \circ f$ is

A) $( - \infty , 0 ) \cup ( 0 , \infty )$
B) $( - \infty , - 1 ) \cup ( - 1 , \infty )$
C) $( - \infty , - 1 ) \cup ( 0 , \infty )$
D) $( - \infty , - 1 ) \cup ( - 1,0 )$
E) $( - \infty , - 1 ) \cup ( - 1,0 ) \cup ( 0 , \infty )$

Question

Let $f ( x ) = x + \frac { 1 } { x }$ and $g ( x ) = \frac { 1 } { x }$ Then the domain of $g \circ f$ is

A) $( - \infty , 0 ) \cup ( 0 , \infty )$
B) $( - \infty , - 1 ) \cup ( - 1 , \infty )$
C) $( - \infty , - 1 ) \cup ( 0 , \infty )$
D) $( - \infty , - 1 ) \cup ( - 1,0 )$
E) $( - \infty , - 1 ) \cup ( - 1,0 ) \cup ( 0 , \infty )$

Quizplus · Accepted Answer

The Answer of Let $f ( x ) = x + \frac { 1 } { x }$ and $g ( x ) = \frac { 1 } { x }$ Then the domain of $g \circ f$ is

A) $( - \infty , 0 ) \cup ( 0 , \infty )$
B) $( - \infty , - 1 ) \cup ( - 1 , \infty )$
C) $( - \infty , - 1 ) \cup ( 0 , \infty )$
D) $( - \infty , - 1 ) \cup ( - 1,0 )$
E) $( - \infty , - 1 ) \cup ( - 1,0 ) \cup ( 0 , \infty )$

Let f(x)=x+1xf ( x ) = x + \frac { 1 } { x }f(x)=x+x1​

Let $f ( x ) = x + \frac { 1 } { x }$