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Case Study 2: 1. Def Scramble2Encrypt(plainText)

Question 30

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Case Study 2:
1. def scramble2Encrypt(plainText):
2. evenChars = ""
3. oddChars = ""
4. charCount = 0
5. for ch in plainText:
6. if charCount % 2 == 0:
7. evenChars = evenChars + ch
8. else:
9. oddChars = oddChars + ch
10. charCount = charCount + 1
11. cipherText = oddChars + evenChars
12. return cipherText
-Refer to the code in the accompanying Case Study 2. Explain how you would reverse the process of scramble2Encrypt in order to decrypt the message.

Correct Answer:

verifed

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To restore the plaintext string, we star...

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