Case Study 1:
1. def drawSquare(aTurtle, side):
2. for i in range(4):
3. aTurtle.forward(side)
4. aTurtle.right(90)
5.
6. def nestedBox(aTurtle, side):
7. if side = 1:
8. drawSquare(aTurtle, side)
9. nestedBox(aTurtle, side - 5)
-Refer to the session in the accompanying Case Study 1. What happens when side is equal to zero?
A) A square of side length zero is drawn.
B) nestedBox returns without doing anything.
C) drawSquare is executed.
D) An infinite recursion occurs.

Question

Case Study 1:
1. def drawSquare(aTurtle, side):
2. for i in range(4):
3. aTurtle.forward(side)
4. aTurtle.right(90)
5.
6. def nestedBox(aTurtle, side):
7. if side >= 1:
8. drawSquare(aTurtle, side)
9. nestedBox(aTurtle, side - 5)
-Refer to the session in the accompanying Case Study 1. What happens when side is equal to zero?
A) A square of side length zero is drawn.
B) nestedBox returns without doing anything.
C) drawSquare is executed.
D) An infinite recursion occurs.

Quizplus · Accepted Answer

nestedBox returns without doing anything when side is equal to zero because the if statement in line 7 evaluates to False.

Case Study 1: 1. Def DrawSquare(aTurtle, Side)