A population of bacteria has a growth curve given by $A=8 e^{2 t}$ , where t is expressed in years. At what value of t does the original number of bacteria double?
A) 0.347 years
B) 0.693 years
C) 1.347 years
D) 1.693 years

Question

Quizplus · Accepted Answer

The original number of bacteria doubles when A = 16. So, we need to solve 8e^(2t) = 16. Dividing both sides by 8, we get e^(2t) = 2. Taking the natural logarithm of both sides, we get 2t = ln(2). Dividing both sides by 2, we get t = ln(2)/2 ≈ 0.347 years.

A Population of Bacteria Has a Growth Curve Given By A=8