Suppose the 2003 prices, per ton, of wine grapes for different kinds of wine are given in the following table. $$\begin{array} { l l }
\text { cellpadding="0" cellspacing="0" width=" } 52 \% \text { " border } \
\text { Variety } & \text { Price } \
\text { Cabernet Sauvignon } & \$ 1,800 \
\text { Merlot } & \$ 1,950 \
\text { Zinfandel } & \$ 1,550 \
\text { Pinot Noir } & \$ 1,350 \
\text { Chardonnay } & \$ 1,550 \
\text { Sauvignon Blanc } & \$ 1,200
\end{array}$$ What are the mean and median? Round your answers to the nearest cent as needed.
A) Mean: $1,566.67 Median: $1,800.00
B) Mean: $1,880.00 Median: none
C) Mean: $1,880.00 Median: $1,550.00
D) Mean: none Median: $1,550.00
E) Mean: $1,566.67 Median: $1,550.00

Question

Suppose the 2003 prices, per ton, of wine grapes for different kinds of wine are given in the following table. $$\begin{array} { l l } 
\text { cellpadding="0" cellspacing="0" width=" } 52 \% \text { " border } \
\text { Variety } & \text { Price } \
\text { Cabernet Sauvignon } & \$ 1,800 \
\text { Merlot } & \$ 1,950 \
\text { Zinfandel } & \$ 1,550 \
\text { Pinot Noir } & \$ 1,350 \
\text { Chardonnay } & \$ 1,550 \
\text { Sauvignon Blanc } & \$ 1,200
\end{array}$$ What are the mean and median? Round your answers to the nearest cent as needed.
A) Mean: $1,566.67 Median: $1,800.00
B) Mean: $1,880.00 Median: none
C) Mean: $1,880.00 Median: $1,550.00
D) Mean: none Median: $1,550.00
E) Mean: $1,566.67 Median: $1,550.00

Quizplus · Accepted Answer

To find the mean, add all the prices together and divide by the number of varieties: $(1800 + 1950 + 1550 + 1350 + 1550 + 1200) / 6 = 9400 / 6 = 1566.67$. For the median, list the prices in ascending order: 1200, 1350, 1550, 1550, 1800, 1950. The median is the average of the two middle numbers, which are both 1550, so the median is also $1550.

Suppose the 2003 Prices, Per Ton, of Wine Grapes for Different