The first three terms of an arithmetic sequence are -318, -306, -294, find the 119th term.
A) 1,734
B) 1,098
C) -37,512
D) 1,110

Question

Quizplus · Accepted Answer

The common difference of the arithmetic sequence is -306 - (-318) = 12. The nth term of an arithmetic sequence is given by a_n = a_1 + (n-1)d, where a_1 is the first term, d is the common difference, and n is the term number. Substituting the given values, a_119 = -318 + (118)(12) = -318 + 1416 = 1098.

The First Three Terms of an Arithmetic Sequence Are -318