The height y (in feet)of a ball that you throw is given by $y = - \frac { 1 } { 190 } x ^ { 2 } + x + 5$ where x is the horizontal distance (in feet)from where you release the ball. How high is the ball when you release it?
A) 5 feet
B) 2.5 feet
C) 1 foot
D) 99 feet
E) $100$ feet

Question

Quizplus · Accepted Answer

When you release the ball, x is equal to 0. Substituting x=0 into the equation gives:
y = - 1/190 (0)^2 + 0 + 5 = 5
Therefore, the ball is 5 feet high when you release it. The answer is (A).

The Height Y (In Feet)of a Ball That You Throw y=−1190x2+x+5y = - \frac { 1 } { 190 } x ^ { 2 } + x + 5y=−1901​x2+x+5

The Height Y (In Feet)of a Ball That You Throw $y = - \frac { 1 } { 190 } x ^ { 2 } + x + 5$