Find the vertex of $y = 6 x ^ { 2 } + 12 x - 6$ .
A) $( - 1 , - 12 )$
B) $( 1,12 )$
C) $( 0 , - 12 )$
D) $( - 2,42 )$
E) $( - 1,12 )$

Question

Quizplus · Accepted Answer

The vertex of a parabola in the form $y = ax^2 + bx + c$ can be found using the formula $(- \frac{b}{2a}, f(- \frac{b}{2a}))$. For $y = 6x^2 + 12x - 6$, $a = 6$, $b = 12$, so the x-coordinate of the vertex is $- \frac{12}{2*6} = -1$. Plugging this back into the equation gives the y-coordinate: $6(-1)^2 + 12(-1) - 6 = 6 - 12 - 6 = -12$. Thus, the vertex is $(-1, -12)$.

Find the Vertex Of y=6x2+12x−6y = 6 x ^ { 2 } + 12 x - 6y=6x2+12x−6

Find the Vertex Of $y = 6 x ^ { 2 } + 12 x - 6$