Use the Quadratic Formula to solve $4 x ^ { 2 } - 12 x + 6 = 0$ , if possible. Round your answer(s)to two decimal places.
A) $x = 18.87 , x = 17.13$
B) $x = - 0.63 , x = - 2.37$
C) $x = 9.46 , x = 2.54$
D) $x = 2.37 , x = 0.63$
E)no solutions

Question

Quizplus · Accepted Answer

The quadratic formula is $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = 4$, $b = -12$, and $c = 6$. Plugging these values in gives $x = \frac{12 \pm \sqrt{(-12)^2 - 4(4)(6)}}{2(4)} = \frac{12 \pm \sqrt{144 - 96}}{8} = \frac{12 \pm \sqrt{48}}{8} = \frac{12 \pm 6.93}{8}$, which simplifies to $x = 2.37$ and $x = 0.63$.

Use the Quadratic Formula to Solve 4x2−12x+6=04 x ^ { 2 } - 12 x + 6 = 04x2−12x+6=0

Use the Quadratic Formula to Solve $4 x ^ { 2 } - 12 x + 6 = 0$