Solve the quadratic equation. $x ^ { 2 } + 6 x + 25 = 0$
A) $x = 14 , x = - 2$
B) $x = 1 , x = - 7$
C) $x = - 6 \pm 8 i$
D) $x = 6 \pm 8 i$
E) $x = - 3 \pm 4 i$

Question

Quizplus · Accepted Answer

The quadratic equation $x^2 + 6x + 25 = 0$ can be solved using the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = 1$, $b = 6$, and $c = 25$. Plugging these values in gives $x = \frac{-6 \pm \sqrt{(-6)^2 - 4(1)(25)}}{2(1)} = \frac{-6 \pm \sqrt{36 - 100}}{2} = \frac{-6 \pm \sqrt{-64}}{2} = \frac{-6 \pm 8i}{2} = -3 \pm 4i$.

Solve the Quadratic Equation x2+6x+25=0x ^ { 2 } + 6 x + 25 = 0x2+6x+25=0

Solve the Quadratic Equation $x ^ { 2 } + 6 x + 25 = 0$