Solve $\sqrt { 2 x } + 7 = 1$ , if possible.
A) x=49
B) x=18
C) x=-7
D) x=7
E)no solution

Question

Quizplus · Accepted Answer

Starting with $\sqrt{2x}+7=1$, we first subtract 7 from both sides: $$\sqrt{2x}=-6.$$ This implies that $2x=(-6)^2=36$, but since we're taking the square root of $2x$, we know that $2x\geq0$. The only number whose square root is equal to $-6$ is $-\sqrt{36}=-6$, which is not a valid value for $x$. Therefore, there is no solution to the equation. Thus, the answer is $\boxed{	extbf{(E)}}$.

Solve 2x+7=1\sqrt { 2 x } + 7 = 12x​+7=1 , If Possible

Solve $\sqrt { 2 x } + 7 = 1$ , If Possible