Solve the equation below by factoring. $$x ^ { 3 } + 5 x ^ { 2 } - 36 x = 0$$
A) $x = 4$ and $x = 9$
B) $x = - 9$ , $x = 0$ and $x = 4$
C) $x = - 4$ , $x = 0$ and $x = 9$
D) $x = - 9$ , $x = - 4$ and $x = 0$
E) $x = 0$ , $x = 4$ and $x = 9$

Question

Quizplus · Accepted Answer

First, factor out an $x$, getting $x(x^2 + 5x - 36) = 0$. Then, factor the quadratic to get $x(x + 9)(x - 4) = 0$. The solutions are $x = 0$, $x = -9$, and $x = 4$.

Solve the Equation Below by Factoring x3+5x2−36x=0x ^ { 3 } + 5 x ^ { 2 } - 36 x = 0x3+5x2−36x=0

Solve the Equation Below by Factoring $x ^ { 3 } + 5 x ^ { 2 } - 36 x = 0$