Factor completely the polynomial below. $3 x ^ { 4 } - 243 x ^ { 2 }$
A) $3 x ^ { 2 } ( x + 9 ) ^ { 2 }$
B) $3 x ^ { 2 } ( x - 9 ) ^ { 2 }$
C) $3 x ( x - 9 ) ^ { 2 } ( x + 9 )$
D) $3 x ( x - 9 ) ( x + 9 ) ^ { 2 }$
E) $3 x ^ { 2 } ( x - 9 ) ( x + 9 )$

Question

Quizplus · Accepted Answer

The polynomial can be factored as $3x^2(x^2 - 81)$, and $x^2 - 81$ is a difference of squares, which factors to $(x - 9)(x + 9)$. Thus, the complete factorization is $3x^2(x - 9)(x + 9)$.

Factor Completely the Polynomial Below 3x4−243x23 x ^ { 4 } - 243 x ^ { 2 }3x4−243x2

Factor Completely the Polynomial Below $3 x ^ { 4 } - 243 x ^ { 2 }$