Solve the linear equation $\frac { 1 } { 4 } x + 2 = \frac { 6 } { 7 } x - 3$ for x .
A) $x = \frac { 140 } { 17 }$
B) $x = - \frac { 140 } { 17 }$
C) $x = \frac { 28 } { 17 }$
D) $x = - \frac { 28 } { 17 }$
E)there is no solution

Question

Quizplus · Accepted Answer

To solve the equation $\frac { 1 } { 4 } x + 2 = \frac { 6 } { 7 } x - 3$, first get all the x terms on one side and the constants on the other. Subtract $\frac { 1 } { 4 } x$ from both sides and add 3 to both sides to get $5 = \frac { 6 } { 7 } x - \frac { 1 } { 4 } x$. To combine the x terms, find a common denominator, which is 28, leading to $5 = \frac { 24 } { 28 } x - \frac { 7 } { 28 } x$, simplifying to $5 = \frac { 17 } { 28 } x$. Solving for x gives $x = \frac { 140 } { 17 }$.

Solve the Linear Equation 14x+2=67x−3\frac { 1 } { 4 } x + 2 = \frac { 6 } { 7 } x - 341​x+2=76​x−3

Solve the Linear Equation $\frac { 1 } { 4 } x + 2 = \frac { 6 } { 7 } x - 3$