Solve $d = \frac { 4 c b } { c - b }$ for c .
A) $c = \frac { b d } { 4 b - 1 }$
B) $c = \frac { 1 } { 4 }$
C) $c = \frac { d ( c - b ) } { 4 b }$
D) $c = - \frac { b d } { 4 b - d }$

Question

Quizplus · Accepted Answer

To solve for $c$, we start with the given equation $d = \frac { 4 c b } { c - b }$. We rearrange it to isolate $c$. Multiplying both sides by $c - b$ and then dividing by $d$ gives us $c - b = \frac{4cb}{d}$. Further rearranging to solve for $c$ leads to $c = - \frac { b d } { 4 b - d }$, which matches choice D.

Solve d=4cbc−bd = \frac { 4 c b } { c - b }d=c−b4cb​

Solve $d = \frac { 4 c b } { c - b }$